P-BIHARMONIC PSEUDO-PARABOLIC EQUATION WITH
LOGARITHMIC NON LINEARITY
Sushmitha Jayachandran
Research Scholar, Department of Mathematics,Central University of Kerala, Kerala - 671 320, India.
E-mail:sushmithaakhilesh@gmail.com
ORCID:
Gnanavel Soundararajan
Assistant Professor, Department of Mathematics,Central University of Kerala, Kerala - 671 320, India.
E-mail:gnanavel.math.bu@gmail.com
ORCID:
Reception: 20/09/2022 Acceptance: 05/10/2022 Publication: 29/12/2022
Suggested citation:
Sushmitha Jayachandran and Gnanavel Soundararajan (2022). p-Biharmonic Pseudo-Parabolic Equation with Logarithmic
Non linearity. 3C TIC. Cuadernos de desarrollo aplicados a las TIC,11 (2), 108-122. https://doi.org/10.17993/3ctic.2022.112.108-
122
https://doi.org/10.17993/3ctic.2022.112.108-122
ABSTRACT
This paper deals with the existence of solutions of a p-biharmonic pseudo parabolic partial differential
equation with logarithmic nonlinearity in a bounded domain. We prove the global existence of the weak
solutions using the Faedo-Galerkin method and applying the concavity approach, that the solutions blow
up at a finite time. Further, we provide a maximal limit for the blow-up time.
KEYWORDS
p-Biharmonic, pseudo-parabolic, global existence, blow up
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
108
P-BIHARMONIC PSEUDO-PARABOLIC EQUATION WITH
LOGARITHMIC NON LINEARITY
Sushmitha Jayachandran
Research Scholar, Department of Mathematics,Central University of Kerala, Kerala - 671 320, India.
E-mail:sushmithaakhilesh@gmail.com
ORCID:
Gnanavel Soundararajan
Assistant Professor, Department of Mathematics,Central University of Kerala, Kerala - 671 320, India.
E-mail:gnanavel.math.bu@gmail.com
ORCID:
Reception: 20/09/2022 Acceptance: 05/10/2022 Publication: 29/12/2022
Suggested citation:
Sushmitha Jayachandran and Gnanavel Soundararajan (2022). p-Biharmonic Pseudo-Parabolic Equation with Logarithmic
Non linearity. 3C TIC. Cuadernos de desarrollo aplicados a las TIC,11 (2), 108-122. https://doi.org/10.17993/3ctic.2022.112.108-
122
https://doi.org/10.17993/3ctic.2022.112.108-122
ABSTRACT
This paper deals with the existence of solutions of a p-biharmonic pseudo parabolic partial differential
equation with logarithmic nonlinearity in a bounded domain. We prove the global existence of the weak
solutions using the Faedo-Galerkin method and applying the concavity approach, that the solutions blow
up at a finite time. Further, we provide a maximal limit for the blow-up time.
KEYWORDS
p-Biharmonic, pseudo-parabolic, global existence, blow up
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
109
1 INTRODUCTION
Here we examine the following problem for a p-biharmonic pseudo-parabolic equation with logarithmic
nonlinearity.
utut+ ∆(|u|p2u)div(|∇u|q2u)=div(|∇u|q2ulog |∇u|)if (x, t)×(0,T),
u=∂u
∂ν =0 if (x, t)×(0,T),
u(x, 0) = u0(x)if x.
(1)
where
RN
(
N
1) represents a bounded domain whose boundary
is smooth enough,
T
(0
,
),
ν
indicates the normal vector on
pointing outward,
u0W2,p
0
(Ω)
\{
0
}
and the condition
2<p<q<p(1 + 2
N+2 )holds for pand q.
Pseudo-parabolic equations address several significant physical processes, like the evolution of two
components of intergalactic material, the leakage of homogeneous fluids through a rock surface, the
biomathematical modeling of a bacterial film, some thin film problems, the straight transmission
of nonlinear, dispersive, long waves, the heat transfer containing two temperatures, a grouping of
populations, etc. Shawalter and Ting [18], [22] first examined the pseudo parabolic equations in 1969.
After their precursory results, there are many papers studied the nonlinear pseudo-parabolic equations,
like semilinear pseudo-parabolic equations, quasilinear pseudo-parabolic equations, and even singular
and degenerate pseudo-parabolic equations (see [1], [28], [4], [6], [15], [24], [25]). A pseudo-parabolic
equation with p-Laplacian
pu
=
div
(
|∇u|p2u
)and logarithmic nonlinearity were studied by Nahn,
and Truong [13] in 2017. Considering the equation,
ututpu=|u|p2ulog |u|
and by using the potential well method proposed by Sattinger [17] and a logarithmic Sobolev inequa-
lity, they proved the existence or nonexistence of global weak solutions. Additionally, they provided
requirements for both the large time decay of weak global solutions and the finite time blow-up of weak
solutions. Later, many authors [26], [27], [23] considered pseudo-parabolic equations with logarithmic
nonlinearity and established results for local and global existence, uniqueness, decay estimate and
asymptotic behaviour of solutions, blow-up results. Logarithmic nonlinearities in parabolic and pseudo-
parabolic equations were studied by Lakshmipriya et.al [11], [10] and other researchers [29], [9], [5] and
they proved the existence of weak solutions and their blow up in finite time. Lower bound of Blow-up
time to a fourth order parabolic equation modelling epitaxial thin film growth
Recently, higher-order equations have gained much importance in studies. Lower bound of Blow-up
time to a fourth order parabolic equation modelling epitaxial thin film growth studied by Liu et.al [3].
The p-biharmonic equation
ut+ ∆(|u|p2u)+λ|u|p2u=0
were studied by Liu and Guo [14], and by using the discrete-time method and uniform estimates, they
established the existence and uniqueness of weak solutions. Hao and Zhou [7] obtained results for blow
up, extinction and non-extinction of solutions for the equation
ut+ ∆(|u|p2u)=|u|q1
|||u|dx.
Wang and Liu [8] studied the p-biharmonic parabolic equation with logarithmic nonlinearity,
ut+ ∆(|u|p2u)=|u|q1ulog |u|
for 2
<p<q<p
(1 +
4
n
)and proved the global existence, blow up, extinction and no extinction of
solutions. Then Liu and Li [2] studied,
ut+ ∆(|u|p2u)=λ|u|q1ulog |u|.
Based on the difference and variation methods, they showed the existence of weak solutions and observed
large-time behaviour and the transmission of solution perturbations for
λ>
0
,p > q > p
2
+1
,p > n
2
.
https://doi.org/10.17993/3ctic.2022.112.108-122
Comert and Piskin [?] studied a p-biharmonic pseudo-parabolic equation with logarithmic nonlinearity
and used the potential well method and logarithmic Sobolev inequality obtained the existence of the
unique global weak solution. In addition, they also exhibited polynomial decay of solutions. Motivated
by these works, we have formulated our problem (1) for a p-biharmonic pseudo-parabolic equation
with logarithmic nonlinearity and studied their existence and non-existence. The problem (1) for the
case
p
=2is already investigated and proved the existence, uniqueness and blow up of solutions
(see [19], [20], [21]).
The rest of this paper is arranged to the two sections below. The preliminary notations, definitions,
and results we need to support our main findings are described in Section 2. Section 3 contains the
major findings of this paper explained in five theorems.
2 PRELIMINARIES
In this section, we provide some fundamental ideas and facts that are necessary for us to explain our
findings. In this article, we follow the notations listed below throughout.
.r
denotes the
Lr
(Ω) norm
for 1
r≤∞
,
.H1
0
denotes the norm in
H1
0
(Ω),(
., .
)
1
denotes the
H1
0
(Ω)-inner product.=,
r
denotes
the Holder conjugate exponent of r>1(that is, r=r
r1).
We define the energy functional Jand the Nehari functional Ias follows:
I,J :W2,p
0(Ω) Rby
J(u)=1
pup
p+q+1
q2∥∇uq
q1
q|∇u|qlog |∇u|dx (2)
I(u)=up
p+∥∇uq
q|∇u|qlog |∇u|dx (3)
Then we have,
J(u)=1
qI(u)+1
p1
qup
p+1
q2∥∇uq
q(4)
We introduce the Nehari manifold as
N={uW2,p
0(Ω)\{0}:I(u)=0}
also define the potential well as
W={uW2,p
0(Ω)\{0}:J(u)< d, I(u)>0}
where d= infu∈N J(u)is referred to as the depth of the potential well.
Definition 1. A function
u
=
u
(
x, t
)is considered to be a weak solution of problem (1) if
u
L(0,T;W2,p
0(Ω)),utL2(0,T;H1
0(Ω)) and validates
(ut)+(ut,ϕ)+(|u|p2u, ϕ)+(|∇u|q2u, ϕ)=(|∇u|q2ulog |∇u|,ϕ)(5)
for all
ϕW2,p
0
(Ω) and a.e 0
tT
along with
u
(
x,
0) =
u0
(
x
)in
W2,p
0
(Ω)
\{
0
}
. Furthermore, it also
agrees the energy inequality
t
0uτ2
H1
0dτ +J(u)J(u0),0<tT. (6)
Lemma 1. [12] Let ρbe a positive number. Then we have the following inequalities:
xplog x()1for all x1
and
|xplog x|≤(ep)1for all 0<x<1.
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
110
1 INTRODUCTION
Here we examine the following problem for a p-biharmonic pseudo-parabolic equation with logarithmic
nonlinearity.
utut+ ∆(|u|p2u)div(|∇u|q2u)=div(|∇u|q2ulog |∇u|)if (x, t)×(0,T),
u=∂u
∂ν =0 if (x, t)×(0,T),
u(x, 0) = u0(x)if x.
(1)
where
RN
(
N
1) represents a bounded domain whose boundary
is smooth enough,
T
(0
,
),
ν
indicates the normal vector on
pointing outward,
u0W2,p
0
(Ω)
\{
0
}
and the condition
2<p<q<p(1 + 2
N+2 )holds for pand q.
Pseudo-parabolic equations address several significant physical processes, like the evolution of two
components of intergalactic material, the leakage of homogeneous fluids through a rock surface, the
biomathematical modeling of a bacterial film, some thin film problems, the straight transmission
of nonlinear, dispersive, long waves, the heat transfer containing two temperatures, a grouping of
populations, etc. Shawalter and Ting [18], [22] first examined the pseudo parabolic equations in 1969.
After their precursory results, there are many papers studied the nonlinear pseudo-parabolic equations,
like semilinear pseudo-parabolic equations, quasilinear pseudo-parabolic equations, and even singular
and degenerate pseudo-parabolic equations (see [1], [28], [4], [6], [15], [24], [25]). A pseudo-parabolic
equation with p-Laplacian
pu
=
div
(
|∇u|p2u
)and logarithmic nonlinearity were studied by Nahn,
and Truong [13] in 2017. Considering the equation,
ututpu=|u|p2ulog |u|
and by using the potential well method proposed by Sattinger [17] and a logarithmic Sobolev inequa-
lity, they proved the existence or nonexistence of global weak solutions. Additionally, they provided
requirements for both the large time decay of weak global solutions and the nite time blow-up of weak
solutions. Later, many authors [26], [27], [23] considered pseudo-parabolic equations with logarithmic
nonlinearity and established results for local and global existence, uniqueness, decay estimate and
asymptotic behaviour of solutions, blow-up results. Logarithmic nonlinearities in parabolic and pseudo-
parabolic equations were studied by Lakshmipriya et.al [11], [10] and other researchers [29], [9], [5] and
they proved the existence of weak solutions and their blow up in finite time. Lower bound of Blow-up
time to a fourth order parabolic equation modelling epitaxial thin film growth
Recently, higher-order equations have gained much importance in studies. Lower bound of Blow-up
time to a fourth order parabolic equation modelling epitaxial thin film growth studied by Liu et.al [3].
The p-biharmonic equation
ut+ ∆(|u|p2u)+λ|u|p2u=0
were studied by Liu and Guo [14], and by using the discrete-time method and uniform estimates, they
established the existence and uniqueness of weak solutions. Hao and Zhou [7] obtained results for blow
up, extinction and non-extinction of solutions for the equation
ut+ ∆(|u|p2u)=|u|q1
|||u|dx.
Wang and Liu [8] studied the p-biharmonic parabolic equation with logarithmic nonlinearity,
ut+ ∆(|u|p2u)=|u|q1ulog |u|
for 2
<p<q<p
(1 +
4
n
)and proved the global existence, blow up, extinction and no extinction of
solutions. Then Liu and Li [2] studied,
ut+ ∆(|u|p2u)=λ|u|q1ulog |u|.
Based on the difference and variation methods, they showed the existence of weak solutions and observed
large-time behaviour and the transmission of solution perturbations for
λ>
0
,p > q > p
2
+1
,p > n
2
.
https://doi.org/10.17993/3ctic.2022.112.108-122
Comert and Piskin [?] studied a p-biharmonic pseudo-parabolic equation with logarithmic nonlinearity
and used the potential well method and logarithmic Sobolev inequality obtained the existence of the
unique global weak solution. In addition, they also exhibited polynomial decay of solutions. Motivated
by these works, we have formulated our problem (1) for a p-biharmonic pseudo-parabolic equation
with logarithmic nonlinearity and studied their existence and non-existence. The problem (1) for the
case
p
=2is already investigated and proved the existence, uniqueness and blow up of solutions
(see [19], [20], [21]).
The rest of this paper is arranged to the two sections below. The preliminary notations, definitions,
and results we need to support our main findings are described in Section 2. Section 3 contains the
major findings of this paper explained in five theorems.
2 PRELIMINARIES
In this section, we provide some fundamental ideas and facts that are necessary for us to explain our
findings. In this article, we follow the notations listed below throughout.
.r
denotes the
Lr
(Ω) norm
for 1
r≤∞
,
.H1
0
denotes the norm in
H1
0
(Ω),(
., .
)
1
denotes the
H1
0
(Ω)-inner product.=,
r
denotes
the Holder conjugate exponent of r>1(that is, r=r
r1).
We define the energy functional Jand the Nehari functional Ias follows:
I,J :W2,p
0(Ω) Rby
J(u)=1
pup
p+q+1
q2∥∇uq
q1
q|∇u|qlog |∇u|dx (2)
I(u)=up
p+∥∇uq
q|∇u|qlog |∇u|dx (3)
Then we have,
J(u)=1
qI(u)+1
p1
qup
p+1
q2∥∇uq
q(4)
We introduce the Nehari manifold as
N={uW2,p
0(Ω)\{0}:I(u)=0}
also define the potential well as
W={uW2,p
0(Ω)\{0}:J(u)< d, I(u)>0}
where d= infu∈N J(u)is referred to as the depth of the potential well.
Definition 1. A function
u
=
u
(
x, t
)is considered to be a weak solution of problem (1) if
u
L(0,T;W2,p
0(Ω)),utL2(0,T;H1
0(Ω)) and validates
(ut)+(ut,ϕ)+(|u|p2u, ϕ)+(|∇u|q2u, ϕ)=(|∇u|q2ulog |∇u|,ϕ)(5)
for all
ϕW2,p
0
(Ω) and a.e 0
tT
along with
u
(
x,
0) =
u0
(
x
)in
W2,p
0
(Ω)
\{
0
}
. Furthermore, it also
agrees the energy inequality
t
0uτ2
H1
0 +J(u)J(u0),0<tT. (6)
Lemma 1. [12] Let ρbe a positive number. Then we have the following inequalities:
xplog x()1for all x1
and
|xplog x|≤(ep)1for all 0<x<1.
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
111
The following lemma is similar to one in [8], [16]. However, we explain the proof with some changes
due to the occurrence of the non-linear logarithmic term
div
(
|∇u|q2ulog |∇u|
)and the q-Laplacian
div(|∇u|q2u).
Lemma 2. For any uW2,p
0(Ω)\{0}, we have the following:
(i) limγ0+J(γu)=0and limγ→∞ J(γu)=−∞;
(ii) d
J(γu)= 1
γI(γu)for γ>0;
(iii) there exists a unique
γ
=
γ
(
u
)
>
0such that
d
J
(
γu
)
|γ=γ
=0. Also
J
(
γu
)is increasing on
0γ, decreasing on γγ<and takes the maximum at γ=γ;
(iv) I(γu)>0for 0
,I(γu)<0for γ<and I(γu)=0.
Proof.
(i) Applying the definition of Jwe have
J(γu)=γp
pup
p+γq(q+ 1)
q2∥∇uq
qγqlog γ
q∥∇uq
qγq
q|∇u|qlog |∇u|dx
so it is evident that limγ0+J(γu)=0and limγ→∞ J(γu)=−∞ since 2<p<q.
(ii) Direct computation yields,
d
J(γu)=γp1up
p+γq1∥∇uq
qγq1|∇u|qlog |γu|dx =1
γI(γu)
(iii) We have,
d
J(γu)=γq1γpqup
p+∥∇uq
qlog γ∥∇uq
q|∇u|qlog |∇u|dx
Now define,
g(γ)=γpqup
p+∥∇uq
qlog γ∥∇uq
q|∇u|qlog |∇u|dx
Then we can observe that gis decreasing since
g(γ)=(pq)γpq1up
p1
γ∥∇uq
q<0
Also, limγ0+g(γ)=and limγ→∞ g(γ)=−∞.
Hence, a unique γwith g(γ)=0is guaranteed.
Also, g(γ)>0for 0
and g(γ)<0for γ<.
Now, since
d
J
(
γu
)=
γq1g
(
γ
)we obtain
d
J
(
γu
)
|γ=γ
=0and also
J
(
γu
)is increasing on
0γ, decreasing on γγ<and takes the maximum at γ=γ.
(iv) (iv) is obvious since I(γu)=γd
J(γu).
The above lemmas are useful to prove the main results in the following section.
https://doi.org/10.17993/3ctic.2022.112.108-122
3 MAIN RESULTS
In this section, we prove the existence of weak local solutions to the problem (1). Further, we show
that the weak solution exists globally using the potential well method when the initial energy of the
system is subcritical and critical. We show that the solution becomes unbounded in finite time and
specifies an upper limit for the blow-up time.
Theorem 1. (The Local existence)
Let
u0W2,p
0
(Ω)
\{
0
}
and 2
<p<q<p
(1 +
2
N+2
). Then a
T>
0and a unique weak solution
u
(
t
)of
problem(1) agreeing the energy inequality
t
0uτ2
H1
0dτ +J(u(t)) J(u0),0tT(7)
and u(0) = u0exists.
Proof.Existence
Let {wi}iNbe an orthonormal basis for W2,p
0(Ω). We use the approximation,
uk(x, t)=
k
i=1
ak,i(t)wi(x),k=1,2,...
where ak,i(t):[0,T]Raccepts the below ODE.
(ukt,w
i)+(ukt,wi)+(|uk|p2uk,wi)+(|∇uk|q2uk,wi)
=(|∇uk|q2uklog |∇uk|,wi)(8)
i=1,2,...,k and
uk(x, 0) =
k
i=1
ak,i(0)wi(x)u0(x)in W2,p
0(Ω)\{0}
By Peano’s theorem, the above ODE has a solution
ak,i
and we can find a
Tk>
0with
ak,i C1
([0
,T
k
]),
which implies ukC1([0,T
k]; W2,p
0(Ω)).
Now by multiplying (8) by
ak,i
(
t
), summing it for
i
=1
,
2
,...,k
and integrating with respect to
t
from
0to twe obtain,
1
2uk2
H1
0+t
0
(ukp
p+∥∇ukq
q)dt =1
2uk(0)2
H1
0+t
0|∇uk|qlog |∇uk|dxdt
That is,
ψk(t)=ψk(0) + t
0|∇uk|qlog |∇uk|dxdt (9)
where
ψk(t)=1
2uk2
H1
0+t
0
(ukp
p+∥∇ukq
q)dt (10)
We obtain the following by employing lemma(1), Gagliardo-Nirenberg interpolation inequality and
Young’s inequality.
|∇uk|qlog |∇uk|dx {xΩ:|∇uk|≥1}|∇uk|qlog |∇uk|dx
()1∥∇ukq+ρ
q+ρ
()1Cq+ρ
1ukθ(q+ρ)
puk(1θ)(q+ρ)
2
ϵukp
p+C(ϵ)uk
p(1θ)(q+ρ)
pθ(q+ρ)
2(11)
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
112
The following lemma is similar to one in [8], [16]. However, we explain the proof with some changes
due to the occurrence of the non-linear logarithmic term
div
(
|∇u|q2ulog |∇u|
)and the q-Laplacian
div(|∇u|q2u).
Lemma 2. For any uW2,p
0(Ω)\{0}, we have the following:
(i) limγ0+J(γu)=0and limγ J(γu)=−∞;
(ii) d
J(γu)= 1
γI(γu)for γ>0;
(iii) there exists a unique
γ
=
γ
(
u
)
>
0such that
d
J
(
γu
)
|γ=γ
=0. Also
J
(
γu
)is increasing on
0γ, decreasing on γγ<and takes the maximum at γ=γ;
(iv) I(γu)>0for 0
,I(γu)<0for γ<and I(γu)=0.
Proof.
(i) Applying the definition of Jwe have
J(γu)=γp
pup
p+γq(q+ 1)
q2∥∇uq
qγqlog γ
q∥∇uq
qγq
q|∇u|qlog |∇u|dx
so it is evident that limγ0+J(γu)=0and limγ J(γu)=−∞ since 2<p<q.
(ii) Direct computation yields,
d
dγ J(γu)=γp1up
p+γq1∥∇uq
qγq1|∇u|qlog |γu|dx =1
γI(γu)
(iii) We have,
d
dγ J(γu)=γq1γpqup
p+∥∇uq
qlog γ∥∇uq
q|∇u|qlog |∇u|dx
Now define,
g(γ)=γpqup
p+∥∇uq
qlog γ∥∇uq
q|∇u|qlog |∇u|dx
Then we can observe that gis decreasing since
g(γ)=(pq)γpq1up
p1
γ∥∇uq
q<0
Also, limγ0+g(γ)=and limγ g(γ)=−∞.
Hence, a unique γwith g(γ)=0is guaranteed.
Also, g(γ)>0for 0
and g(γ)<0for γ<.
Now, since
d
J
(
γu
)=
γq1g
(
γ
)we obtain
d
J
(
γu
)
|γ=γ
=0and also
J
(
γu
)is increasing on
0γ, decreasing on γγ<and takes the maximum at γ=γ.
(iv) (iv) is obvious since I(γu)=γd
J(γu).
The above lemmas are useful to prove the main results in the following section.
https://doi.org/10.17993/3ctic.2022.112.108-122
3 MAIN RESULTS
In this section, we prove the existence of weak local solutions to the problem (1). Further, we show
that the weak solution exists globally using the potential well method when the initial energy of the
system is subcritical and critical. We show that the solution becomes unbounded in finite time and
specifies an upper limit for the blow-up time.
Theorem 1. (The Local existence)
Let
u0W2,p
0
(Ω)
\{
0
}
and 2
<p<q<p
(1 +
2
N+2
). Then a
T>
0and a unique weak solution
u
(
t
)of
problem(1) agreeing the energy inequality
t
0uτ2
H1
0 +J(u(t)) J(u0),0tT(7)
and u(0) = u0exists.
Proof.Existence
Let {wi}iNbe an orthonormal basis for W2,p
0(Ω). We use the approximation,
uk(x, t)=
k
i=1
ak,i(t)wi(x),k=1,2,...
where ak,i(t):[0,T]Raccepts the below ODE.
(ukt,w
i)+(ukt,wi)+(|uk|p2uk,wi)+(|∇uk|q2uk,wi)
=(|∇uk|q2uklog |∇uk|,wi)(8)
i=1,2,...,k and
uk(x, 0) =
k
i=1
ak,i(0)wi(x)u0(x)in W2,p
0(Ω)\{0}
By Peano’s theorem, the above ODE has a solution
ak,i
and we can find a
Tk>
0with
ak,i C1
([0
,T
k
]),
which implies ukC1([0,T
k]; W2,p
0(Ω)).
Now by multiplying (8) by
ak,i
(
t
), summing it for
i
=1
,
2
,...,k
and integrating with respect to
t
from
0to twe obtain,
1
2uk2
H1
0+t
0
(ukp
p+∥∇ukq
q)dt =1
2uk(0)2
H1
0+t
0|∇uk|qlog |∇uk|dxdt
That is,
ψk(t)=ψk(0) + t
0|∇uk|qlog |∇uk|dxdt (9)
where
ψk(t)=1
2uk2
H1
0+t
0
(ukp
p+∥∇ukq
q)dt (10)
We obtain the following by employing lemma(1), Gagliardo-Nirenberg interpolation inequality and
Young’s inequality.
|∇uk|qlog |∇uk|dx {xΩ:|∇uk|≥1}|∇uk|qlog |∇uk|dx
()1∥∇ukq+ρ
q+ρ
()1Cq+ρ
1ukθ(q+ρ)
puk(1θ)(q+ρ)
2
ϵukp
p+C(ϵ)uk
p(1θ)(q+ρ)
pθ(q+ρ)
2(11)
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
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where θ=1
n+1
21
q+ρ2
n+1
21
p1(0,1),
C(ϵ)=
θ(q+ρ)θ(q+ρ)
θ(q+ρ)ppθ(q+ρ)
p()1Cq+ρ
1p
pθ(q+ρ)and,
ρis chosen so that 2<q+ρ<p(1 + 2
n+2 ).
Let β=p(1θ)(q+ρ)
2(pθ(q+ρ)) =np+(pn)(q+ρ)
p(4+n)(n+2)(q+ρ). Then β>1and
|∇uk|qlog |∇uk|dx ϵukp
p+C(ϵ)uk2β
2(12)
Then (9) implies that,
ψk(t)ψk(0) + ϵt
0ukp
pdt +C(ϵ)t
0uk2β
2dt
C2+ϵψk(t)+C(ϵ)2βt
01
2uk2
H1
0β
+s
0
(ukp
p+∥∇ukq
q)dsβdt
C2+ϵψk(t)+C3t
0
ψk(t)βdt
Hence we get,
ψk(t)C4+C5t
0
ψk(t)βdt
Then the Gronwall-Bellman-Bihari type integral inequality gives a Tsuch that 0<T < C1β
4
C5(1β)and
ψk(t)CTfor all t[0,T].(13)
Hence the solution of (8) exists in [0,T]for all k.
Now multiplying (8) by a
k,i(t)and summing for i=1,2,...,k we get,
(ukt,u
kt)+(ukt,ukt)+(|uk|p2uk,ukt)+(|∇uk|q2uk,ukt)
=(|∇uk|q2uklog |∇uk|,ukt)
integrating with respect to t,
t
0ukt2
H1
0dt +J(uk(t)) = J(uk(0)) for all t[0,T].(14)
As contrast to that, a constant C6>0satisfying
J(uk(0)) C6for all k. (15)
exists since
uk
(0)
u0
and by the continuity of
J
. Then from (12),(13),(14) and (15) we can see that
C6t
0ukt2
H1
0dt +1
pukp
p+q+1
q2∥∇ukq
q1
q|∇uk|qlog |∇uk|dx
t
0ukt2
H1
0dt +1
pϵ
qukp
p+q+1
q2∥∇ukq
qC(ϵ)
quk2β
H1
0
t
0ukt2
H1
0dt +1
pϵ
qukp
p+q+1
q2∥∇ukq
qC(ϵ)
q2βCβ
T
Let ˜
C=C6+C(ϵ)2β
qCβ
T. Then we gain that
t
0ukt2
2dt ˜
C
t
0∥∇ukt2
2dt ˜
C
ukp
p<˜
C1
pϵ
q1
∥∇ukq
q<˜
Cq2
q+1
https://doi.org/10.17993/3ctic.2022.112.108-122
Thus we have
{uk}kN
is bounded in
L
(0
,T
;
W2,p
0
(Ω)) and
{ukt}kN
is bounded in
L2
(0
,T
;
H1
0
(Ω)).
Hence there exists a subsequence, however indicated by {uk}kNwhich agrees,
ukuweakly* in L(0,T;W2,p
0(Ω))
ukt utweakly in L2(0,T;H1
0(Ω))
ukuweakly* in L(0,T;W1,q
0(Ω))
since
ukt utweakly in L2(0,T;L2(Ω))
by Aubin-Lions lemma we get,
ukustrongly in C(0,T;L2(Ω))
Therefore,
|uk|p2ukξ1weakly* in L(0,T;W2,p
0(Ω))
and,
|∇uk|q2ukξ2weakly* in L(0,T;W1,q
0(Ω))
where
W2,p
0
(Ω) is the dual space of
W2,p
0
(Ω) and
W1,q
0
(Ω) is the dual space of
W1,q
0
(Ω). Now from
the theory of monotone operators, it concludes,
ξ1=|u|p2uand ξ2=|∇u|q2u.
Now let Φ(u)=|u|q2ulog |u|.Wehave
uk→∇uweakly* in L(0,T;L2(Ω))
ukt →∇utweakly in L2(0,T;L2(Ω))
Therefore,
uk→∇ustrongly in C(0,T;L2(Ω))
and
Φ(uk)Φ(u)a.e in ×(0,T)
We again use Lemma(1) and Gagliardo-Nirenberg interpolation inequality to emerge the below.
(Φ(uk))qdx {xΩ:|∇uk|≤1}|∇uk|q1|log |∇uk||q
dx
+{xΩ:|∇uk|≥1}|∇uk|q1|log |∇uk||q
dx
(e(q1))q||+()q∥∇ukr
r
(e(q1))q||+()qCr
7ukrα
pukr(1α)
2
<C
8
where r=(q1+µ)q,q=q
q1and α=1
n+1
21
r2
n+1
21
p1. Hence,
Φ(uk)Φ(u)weakly* in L(0,T;Lq(Ω))
Now for a fixed iin (8) letting ktends to we get,
(ut,w
i)+(ut,wi)+(|u|p2u, wi)+(|∇u|q2u, wi)=(|∇u|q2ulog |∇u|,wi)
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
114
where θ=1
n+1
21
q+ρ2
n+1
21
p1(0,1),
C(ϵ)=
θ(q+ρ)θ(q+ρ)
θ(q+ρ)ppθ(q+ρ)
p()1Cq+ρ
1p
pθ(q+ρ)and,
ρis chosen so that 2<q+ρ<p(1 + 2
n+2 ).
Let β=p(1θ)(q+ρ)
2(pθ(q+ρ)) =np+(pn)(q+ρ)
p(4+n)(n+2)(q+ρ). Then β>1and
|∇uk|qlog |∇uk|dx ϵukp
p+C(ϵ)uk2β
2(12)
Then (9) implies that,
ψk(t)ψk(0) + ϵt
0ukp
pdt +C(ϵ)t
0uk2β
2dt
C2+ϵψk(t)+C(ϵ)2βt
01
2uk2
H1
0β
+s
0
(ukp
p+∥∇ukq
q)dsβdt
C2+ϵψk(t)+C3t
0
ψk(t)βdt
Hence we get,
ψk(t)C4+C5t
0
ψk(t)βdt
Then the Gronwall-Bellman-Bihari type integral inequality gives a Tsuch that 0<T < C1β
4
C5(1β)and
ψk(t)CTfor all t[0,T].(13)
Hence the solution of (8) exists in [0,T]for all k.
Now multiplying (8) by a
k,i(t)and summing for i=1,2,...,k we get,
(ukt,u
kt)+(ukt,ukt)+(|uk|p2uk,ukt)+(|∇uk|q2uk,ukt)
=(|∇uk|q2uklog |∇uk|,ukt)
integrating with respect to t,
t
0ukt2
H1
0dt +J(uk(t)) = J(uk(0)) for all t[0,T].(14)
As contrast to that, a constant C6>0satisfying
J(uk(0)) C6for all k. (15)
exists since
uk
(0)
u0
and by the continuity of
J
. Then from (12),(13),(14) and (15) we can see that
C6t
0ukt2
H1
0dt +1
pukp
p+q+1
q2∥∇ukq
q1
q|∇uk|qlog |∇uk|dx
t
0ukt2
H1
0dt +1
pϵ
qukp
p+q+1
q2∥∇ukq
qC(ϵ)
quk2β
H1
0
t
0ukt2
H1
0dt +1
pϵ
qukp
p+q+1
q2∥∇ukq
qC(ϵ)
q2βCβ
T
Let ˜
C=C6+C(ϵ)2β
qCβ
T. Then we gain that
t
0ukt2
2dt ˜
C
t
0∥∇ukt2
2dt ˜
C
ukp
p<˜
C1
pϵ
q1
∥∇ukq
q<˜
Cq2
q+1
https://doi.org/10.17993/3ctic.2022.112.108-122
Thus we have
{uk}kN
is bounded in
L
(0
,T
;
W2,p
0
(Ω)) and
{ukt}kN
is bounded in
L2
(0
,T
;
H1
0
(Ω)).
Hence there exists a subsequence, however indicated by {uk}kNwhich agrees,
ukuweakly* in L(0,T;W2,p
0(Ω))
ukt utweakly in L2(0,T;H1
0(Ω))
ukuweakly* in L(0,T;W1,q
0(Ω))
since
ukt utweakly in L2(0,T;L2(Ω))
by Aubin-Lions lemma we get,
ukustrongly in C(0,T;L2(Ω))
Therefore,
|uk|p2ukξ1weakly* in L(0,T;W2,p
0(Ω))
and,
|∇uk|q2ukξ2weakly* in L(0,T;W1,q
0(Ω))
where
W2,p
0
(Ω) is the dual space of
W2,p
0
(Ω) and
W1,q
0
(Ω) is the dual space of
W1,q
0
(Ω). Now from
the theory of monotone operators, it concludes,
ξ1=|u|p2uand ξ2=|∇u|q2u.
Now let Φ(u)=|u|q2ulog |u|.Wehave
uk→∇uweakly* in L(0,T;L2(Ω))
ukt →∇utweakly in L2(0,T;L2(Ω))
Therefore,
uk→∇ustrongly in C(0,T;L2(Ω))
and
Φ(uk)Φ(u)a.e in ×(0,T)
We again use Lemma(1) and Gagliardo-Nirenberg interpolation inequality to emerge the below.
(Φ(uk))qdx {xΩ:|∇uk|≤1}|∇uk|q1|log |∇uk||q
dx
+{xΩ:|∇uk|≥1}|∇uk|q1|log |∇uk||q
dx
(e(q1))q||+()q∥∇ukr
r
(e(q1))q||+()qCr
7uk
pukr(1α)
2
<C
8
where r=(q1+µ)q,q=q
q1and α=1
n+1
21
r2
n+1
21
p1. Hence,
Φ(uk)Φ(u)weakly* in L(0,T;Lq(Ω))
Now for a fixed iin (8) letting ktends to we get,
(ut,w
i)+(ut,wi)+(|u|p2u, wi)+(|∇u|q2u, wi)=(|∇u|q2ulog |∇u|,wi)
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
115
for all i=1,2,...,k. Then for all ϕW2,p
0(Ω) and for a.e. t[0,T],
(ut)+(ut,ϕ)+(|u|p2u, ϕ)+(|∇u|q2u, ϕ)=(|∇u|q2ulog |∇u|,ϕ)
and u(x, 0) = u0(x)in W02,p
2(Ω)\{0}.
Uniqueness
Let uand ˜ube two weak solutions of problem (1). For any ϕH2
0(Ω), it is noted that,
(ut)+(ut,ϕ)+(|u|p2u, ϕ)+(|∇u|q2u, ϕ)=(|∇u|q2ulog |∇u|,ϕ)
ut)+(˜ut,ϕ)+(|∆˜u|p2∆˜u, ϕ)+(|∇˜u|q2˜u, ϕ)=(|∇˜u|q2˜ulog |∇˜u|,ϕ)
On subtraction of one equation from the other and taking ϕ=u˜u, the above yields that
(ϕt)+(ϕt,ϕ)+
(|u|p2u−|∆˜u|p2∆˜u)(∆u∆˜u)dx
+
(|∇u|q2u |∇˜u|q2˜u)(u−∇˜u)dx
=
(|∇u|q2ulog |∇u|−|˜u|q2˜ulog |∇˜u|)(u−∇˜u)dx
Then by the monotonicity of q-Laplacian
div
(
|∇u|q2u
)and the p-Biharmonic operator ∆(
|
u|p2
u
)
and by the Lipschitz continuity of |x|q2xlog |x|we get,
(ϕt)1L
(u−∇˜u)2dx
where L>0is the Lipschitz constant. Thus we obtain,
(ϕt)1L∥∇ϕ2
2Lϕ2
H1
0
By the integration from 0to twith respect to twe obtain that,
ϕ2
H1
0−∥ϕ(0)2
H1
0Lt
0ϕ2
H1
0dt.
Since ϕ(0) = u(0) ˜u(0) = 0, apply Gronwall’s inequality to gain,
ϕ2
H1
0=0
Therefore, ϕ=0a.e. in ×(0,T). That is, uua.e. in ×(0,T).
Energy inequality
Let χC[0,T]be a non-negative function. Then (14) implies
T
0
χ(t)t
0ukt2
H1
0dsdt +T
0
J(uk(t))χ(t)dt =T
0
J(uk(0))χ(t)dt
Since, we have the lower semi-continuity
T
0J
(
uk
(
t
))
χ
(
t
)
dt
with respect to the weak topology of
L2(0,T;W2,p
0(Ω)).T
0
J(u(t))χ(t)dt lim inf
k→∞ T
0
J(uk(t))χ(t)dt
also T
0J(uk(0))χ(t)dt T
0J(u0)χ(t)dt as k→∞. Thus we get,
T
0
χ(t)t
0ut2
H1
0dsdt +T
0
J(u(t))χ(t)dt T
0
J(u0)χ(t)dt
Since χ(t)is arbitrary,
t
0uτ2
H1
0 +J(u(t)) J(u0)for 0tT.
Hence the proof is complete.
Next theorem address the case of the initial energy of the system is sub-critical, i.e,
J
(
u0
)
<d
. We
will demonstrate the existence of weak global solutions.
https://doi.org/10.17993/3ctic.2022.112.108-122
Theorem 2. (Global Existence for J(u0)<d)
A unique global weak solution usatisfying the energy estimate,
t
0uτ2
H1
0dτ +J(u(t)) J(u0)for 0t<(16)
exists for problem(1) if the conditions
J
(
u0
)
<d
and
I
(
u0
)
>
0holds for the initial value
u0
W2,p
0(Ω)\{0}.
Proof. Define
{wi}iN
and
{uk}kN
as in the proof of Theorem(1). Multiplying (8) by
a
k,i
(
t
)and
summing over iand integrating with respect to tfrom 0to twe identify,
t
0ukt2
H1
0dt +J(uk(t)) = J(uk(0)) for all t[0,T
max)(17)
where Tmax is the maximum time for solution uk(x, t)to exist.
We have J(uk(0)) J(u0)as k→∞and J(u0)<d. Therefore,
t
0ukt2
H1
0dt +J(uk(t)) < d, t [0,T
max)(18)
Since
I
(
u0
)
>
0we have
I
(
uk
(0))
>
0for sufficiently large
k
. We claim that
I
(
uk
)
>
0for sufficiently
large
k
. Otherwise we can locate a
t0
such that
I
(
uk
(
t0
)) = 0,
uk
(
t0
)
=0. Then
uk
(
t0
)
∈N
and
J(uk(t0)) d, which is a contradiction to (18).
Therefore I(uk)>0for appropriately large k.
Then we get,
J(uk)=1
qI(uk)+1
p1
qukp
p+1
q2∥∇ukq
q>0
Therefore, t
0ukt2
H1
0dt < d
also 1
p1
qukp
p+1
q2∥∇ukq
q<J(uk)<d
Let K0= min{1
p1
q,1
q2}and K=d+d
K0then
ukp
p+∥∇ukq
q< d/K0
and t
0ukt2
H1
0dt +ukp
p+∥∇ukq
q<K (19)
where
K>
0. Hence we take
Tmax
=
. Now it is noticeable that problem (1) has a weak global
solution by applying identical ideas used to prove the Theorem(1), and the solution
u
also agrees with
the energy inequality t
0uτ2
H1
0dτ +J(u(t)) J(u0),0t<.
We will explain the global existence of weak solutions in the following theorem for the critical initial
energy. That is when J(u0)=d.
Theorem 3. (Global existence for J(u0)=d)
Observe the conditions
J
(
u0
)=
d
and
I
(
u0
)
>
0holds for the initial value
u0W2,p
0
(Ω)
\{
0
}
.
Subsequently problem(1) possesses a unique global weak solution
uL
(0
,T
;
W2,p
0
(Ω)) with
ut
L2(0,T;L2(Ω)) for 0tTand it also accepts the energy estimate (16).
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
116
for all i=1,2,...,k. Then for all ϕW2,p
0(Ω) and for a.e. t[0,T],
(ut)+(ut,ϕ)+(|u|p2u, ϕ)+(|∇u|q2u, ϕ)=(|∇u|q2ulog |∇u|,ϕ)
and u(x, 0) = u0(x)in W02,p
2(Ω)\{0}.
Uniqueness
Let uand ˜ube two weak solutions of problem (1). For any ϕH2
0(Ω), it is noted that,
(ut)+(ut,ϕ)+(|u|p2u, ϕ)+(|∇u|q2u, ϕ)=(|∇u|q2ulog |∇u|,ϕ)
ut)+(˜ut,ϕ)+(|∆˜u|p2∆˜u, ϕ)+(|∇˜u|q2˜u, ϕ)=(|∇˜u|q2˜ulog |∇˜u|,ϕ)
On subtraction of one equation from the other and taking ϕ=u˜u, the above yields that
(ϕt)+(ϕt,ϕ)+
(|u|p2u−|∆˜u|p2∆˜u)(∆u∆˜u)dx
+
(|∇u|q2u |∇˜u|q2˜u)(u−∇˜u)dx
=
(|∇u|q2ulog |∇u|−|˜u|q2˜ulog |∇˜u|)(u−∇˜u)dx
Then by the monotonicity of q-Laplacian
div
(
|∇u|q2u
)and the p-Biharmonic operator ∆(
|
u|p2
u
)
and by the Lipschitz continuity of |x|q2xlog |x|we get,
(ϕt)1L
(u−∇˜u)2dx
where L>0is the Lipschitz constant. Thus we obtain,
(ϕt)1L∥∇ϕ2
2Lϕ2
H1
0
By the integration from 0to twith respect to twe obtain that,
ϕ2
H1
0−∥ϕ(0)2
H1
0Lt
0ϕ2
H1
0dt.
Since ϕ(0) = u(0) ˜u(0) = 0, apply Gronwall’s inequality to gain,
ϕ2
H1
0=0
Therefore, ϕ=0a.e. in ×(0,T). That is, uua.e. in ×(0,T).
Energy inequality
Let χC[0,T]be a non-negative function. Then (14) implies
T
0
χ(t)t
0ukt2
H1
0dsdt +T
0
J(uk(t))χ(t)dt =T
0
J(uk(0))χ(t)dt
Since, we have the lower semi-continuity
T
0J
(
uk
(
t
))
χ
(
t
)
dt
with respect to the weak topology of
L2(0,T;W2,p
0(Ω)).T
0
J(u(t))χ(t)dt lim inf
k T
0
J(uk(t))χ(t)dt
also T
0J(uk(0))χ(t)dt T
0J(u0)χ(t)dt as k→∞. Thus we get,
T
0
χ(t)t
0ut2
H1
0dsdt +T
0
J(u(t))χ(t)dt T
0
J(u0)χ(t)dt
Since χ(t)is arbitrary,
t
0uτ2
H1
0dτ +J(u(t)) J(u0)for 0tT.
Hence the proof is complete.
Next theorem address the case of the initial energy of the system is sub-critical, i.e,
J
(
u0
)
<d
. We
will demonstrate the existence of weak global solutions.
https://doi.org/10.17993/3ctic.2022.112.108-122
Theorem 2. (Global Existence for J(u0)<d)
A unique global weak solution usatisfying the energy estimate,
t
0uτ2
H1
0 +J(u(t)) J(u0)for 0t<(16)
exists for problem(1) if the conditions
J
(
u0
)
<d
and
I
(
u0
)
>
0holds for the initial value
u0
W2,p
0(Ω)\{0}.
Proof. Define
{wi}iN
and
{uk}kN
as in the proof of Theorem(1). Multiplying (8) by
a
k,i
(
t
)and
summing over iand integrating with respect to tfrom 0to twe identify,
t
0ukt2
H1
0dt +J(uk(t)) = J(uk(0)) for all t[0,T
max)(17)
where Tmax is the maximum time for solution uk(x, t)to exist.
We have J(uk(0)) J(u0)as k→∞and J(u0)<d. Therefore,
t
0ukt2
H1
0dt +J(uk(t)) < d, t [0,T
max)(18)
Since
I
(
u0
)
>
0we have
I
(
uk
(0))
>
0for sufficiently large
k
. We claim that
I
(
uk
)
>
0for sufficiently
large
k
. Otherwise we can locate a
t0
such that
I
(
uk
(
t0
)) = 0,
uk
(
t0
)
=0. Then
uk
(
t0
)
∈N
and
J(uk(t0)) d, which is a contradiction to (18).
Therefore I(uk)>0for appropriately large k.
Then we get,
J(uk)=1
qI(uk)+1
p1
qukp
p+1
q2∥∇ukq
q>0
Therefore, t
0ukt2
H1
0dt < d
also 1
p1
qukp
p+1
q2∥∇ukq
q<J(uk)<d
Let K0= min{1
p1
q,1
q2}and K=d+d
K0then
ukp
p+∥∇ukq
q< d/K0
and t
0ukt2
H1
0dt +ukp
p+∥∇ukq
q<K (19)
where
K>
0. Hence we take
Tmax
=
. Now it is noticeable that problem (1) has a weak global
solution by applying identical ideas used to prove the Theorem(1), and the solution
u
also agrees with
the energy inequality t
0uτ2
H1
0 +J(u(t)) J(u0),0t<.
We will explain the global existence of weak solutions in the following theorem for the critical initial
energy. That is when J(u0)=d.
Theorem 3. (Global existence for J(u0)=d)
Observe the conditions
J
(
u0
)=
d
and
I
(
u0
)
>
0holds for the initial value
u0W2,p
0
(Ω)
\{
0
}
.
Subsequently problem(1) possesses a unique global weak solution
uL
(0
,T
;
W2,p
0
(Ω)) with
ut
L2(0,T;L2(Ω)) for 0tTand it also accepts the energy estimate (16).
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
117
Proof. Let
ηj
=1
1
j,j
=1
,
2
,...
then
ηj
1when
j→∞
. Take into account the below problem:
utut+ ∆(|u|p2u)div(|∇u|q2u)=div(|∇u|q2ulog |∇u|)if (x, t)×(0,T),
u=∂u
∂ν =0 if (x, t)×(0,T),
u(x, 0) = ηju0(x)=uj
0if x.
(20)
Since I(u0)>0, lemma (2)(iv) gives a γ>1with I(γu0)=0.
Again from lemma (2)(iii) and (iv) we gain I(ηju0)>0and J(ηju0)<J(u0)since ηj<1
.
Thus we have J(uj
0)<dand I(uj
0)>0.
Then by Theorem(2), for each
j
problem (20) has a global weak solution
ujL
(0
,T
;
Wp2
0
(Ω)) with
uj
tL2(0,T;L2(Ω)) which satisfies the energy inequality,
t
0uj
τ2
H1
0 +J(uj(t)) J(uj
0)for 0t<.
Thus we have t
0uj
τ2
H1
0 +J(uj)<d for 0t<.
Now by applying ideas similar to the one used to prove Theorem(1), we obtain a subsequence of
{uj}jN
converging to a function
u
, which is a weak solution of problem (1). It also fulfils the energy inequality
(16). The solution’s uniqueness can also be proved as in Theorem(1).
Hence the proof is over.
The following theorem gives the blow-up of solutions for the subcritical initial energy and an upper
bound for blow up time.
Theorem 4. (Blow up for J(u0)<d)
Let
u0H2
0
(Ω)
\{
0
}
,
J
(
u0
)
<d
and
I
(
u0
)
<
0. Then the weak solution
u
of problem (1) blows up in a
finite time
T
in the notion,
limtT
u2
H1
0
=
. Furthermore, the upper bound of blow-up time
T
is
given by
T4(q1)u02
H1
0
q(q2)2(dJ(u0)).
Proof.First we prove
J
(
u
(
t
))
<d
and
I
(
u
(
t
))
<
0for
t
[0
,T
], where
T
indicates the maximum time
for which u(x, t)exists.
We have J(u(t)) <J(u0)<dby (6).
If we can choose a
t0
(0
,T
)with
I
(
u
(
t0
))=0or
J
(
u
(
t0
)) =
d
, since
J
(
u
(
t0
))
<d
, we must have
I(u(t0))=0.
Which implies u(t0)∈Nand thus dJ(u(t0)), a contradiction.
Hence, J(u(t)) <dand I(u(t)) <0for t[0,T]. Now define
P(t)=t
0u2
H1
0dt
Then,
P(t)=u2
H1
0
and
P′′(t)=2(u, ut)1=2I(u)>0
Hence for t>0,P(t)≥P(0) = u02
H1
0>0.
Now fix t1>0. Then for t1t<,
P(t)≥P(t1)t1u02
H1
0>0
By Holder’s inequality, we have,
1
4(P(t)−P(0))2t
0u2
H1
0dt t
0ut2
H1
0dt (21)
https://doi.org/10.17993/3ctic.2022.112.108-122
Since I(u(t)) <0, Lemma 2 (iv), gives a γwith 0
<1and I(γu)=0. Therefore,
d1
p1
q(γ)pup
p+1
q2(γ)q∥∇uq
q
1
p1
qup
p+1
q2∥∇uq
q(22)
Now by using (4),(6) and (22) we see that,
P′′(t)2q(dJ(u0))+2qt
0ut2
H1
0dt (23)
Then from (21) and (23) it follows that
P′′(t)P(t)q
2(P(t)−P(0))2≥P(t)2q(dJ(u0)) >0for t[t1,)(24)
Now choose ˜
T>0large enough to introduce,
Q(t)=P(t)+(˜
Tt)u02
H1
0for t[t1,˜
T]
Then Q(t)≥P(t)>0for t[t1,˜
T],Q(t)=P(t)−P(0) >0and Q′′(t)=P′′(t)>0.
Hence from (24) we observe,
Q(t)Q′′(t)q
2(Q(t))2≥P(t)2q(dJ(u0)) + P′′(t)( ˜
Tt)u02
H1
0>0(25)
Now define
R(t)=Q(t)q2
2
Then,
R(t)=q2
2Q(t)q
2Q(t)
and
R′′(t)=q2
2Q(t)q+2
2q
2(Q(t))2−Q(t)Q′′(t)<0
Hence
R
(
t
)is a concave function in [
t1,˜
T
]for any sufficiently large
˜
T >t
1
. Also since
R
(
t1
)
>
0
and
R′′
(
t1
)
<
0, there appears a finite time
T>t
1>
0having
limtT
R
(
t
)=0. That yields
limtT
Q(t)=+, which in turn gives limtT
P(t)=+. Hence we get
lim
tT
u2
H1
0=+.
To obtain an upper limit for blow-up time we define,
S(t)=P(t)+(Tt)u02
H1
0+σ(t+φ)2for t[0,T
]
where the constants σ, φ > 0will be given later.
Then,
S(t)=u2
H1
0−∥u02
H1
0+2σ(t+φ)>2σ(t+φ)>0(26)
also by (23) we get,
S′′(t)2q(dJ(u0))+2qt
0ut2
H1
0dt +2σ(27)
By Schwartz’s inequality, we have,
t
0
d
dtu2
H1
0dt 2t
0u2
H1
0dt t
0ut2
H1
0dt (28)
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
118
Proof. Let
ηj
=1
1
j,j
=1
,
2
,...
then
ηj
1when
j→∞
. Take into account the below problem:
utut+ ∆(|u|p2u)div(|∇u|q2u)=div(|∇u|q2ulog |∇u|)if (x, t)×(0,T),
u=∂u
∂ν =0 if (x, t)×(0,T),
u(x, 0) = ηju0(x)=uj
0if x.
(20)
Since I(u0)>0, lemma (2)(iv) gives a γ>1with I(γu0)=0.
Again from lemma (2)(iii) and (iv) we gain I(ηju0)>0and J(ηju0)<J(u0)since ηj<1
.
Thus we have J(uj
0)<dand I(uj
0)>0.
Then by Theorem(2), for each
j
problem (20) has a global weak solution
ujL
(0
,T
;
Wp2
0
(Ω)) with
uj
tL2(0,T;L2(Ω)) which satisfies the energy inequality,
t
0uj
τ2
H1
0dτ +J(uj(t)) J(uj
0)for 0t<.
Thus we have t
0uj
τ2
H1
0dτ +J(uj)<d for 0t<.
Now by applying ideas similar to the one used to prove Theorem(1), we obtain a subsequence of
{uj}jN
converging to a function
u
, which is a weak solution of problem (1). It also fulfils the energy inequality
(16). The solution’s uniqueness can also be proved as in Theorem(1).
Hence the proof is over.
The following theorem gives the blow-up of solutions for the subcritical initial energy and an upper
bound for blow up time.
Theorem 4. (Blow up for J(u0)<d)
Let
u0H2
0
(Ω)
\{
0
}
,
J
(
u0
)
<d
and
I
(
u0
)
<
0. Then the weak solution
u
of problem (1) blows up in a
finite time
T
in the notion,
limtT
u2
H1
0
=
. Furthermore, the upper bound of blow-up time
T
is
given by
T4(q1)u02
H1
0
q(q2)2(dJ(u0)).
Proof.First we prove
J
(
u
(
t
))
<d
and
I
(
u
(
t
))
<
0for
t
[0
,T
], where
T
indicates the maximum time
for which u(x, t)exists.
We have J(u(t)) <J(u0)<dby (6).
If we can choose a
t0
(0
,T
)with
I
(
u
(
t0
))=0or
J
(
u
(
t0
)) =
d
, since
J
(
u
(
t0
))
<d
, we must have
I(u(t0))=0.
Which implies u(t0)∈Nand thus dJ(u(t0)), a contradiction.
Hence, J(u(t)) <dand I(u(t)) <0for t[0,T]. Now define
P(t)=t
0u2
H1
0dt
Then,
P(t)=u2
H1
0
and
P′′(t)=2(u, ut)1=2I(u)>0
Hence for t>0,P(t)≥P(0) = u02
H1
0>0.
Now fix t1>0. Then for t1t<,
P(t)≥P(t1)t1u02
H1
0>0
By Holder’s inequality, we have,
1
4(P(t)−P(0))2t
0u2
H1
0dt t
0ut2
H1
0dt (21)
https://doi.org/10.17993/3ctic.2022.112.108-122
Since I(u(t)) <0, Lemma 2 (iv), gives a γwith 0
<1and I(γu)=0. Therefore,
d1
p1
q(γ)pup
p+1
q2(γ)q∥∇uq
q
1
p1
qup
p+1
q2∥∇uq
q(22)
Now by using (4),(6) and (22) we see that,
P′′(t)2q(dJ(u0))+2qt
0ut2
H1
0dt (23)
Then from (21) and (23) it follows that
P′′(t)P(t)q
2(P(t)−P(0))2≥P(t)2q(dJ(u0)) >0for t[t1,)(24)
Now choose ˜
T>0large enough to introduce,
Q(t)=P(t)+(˜
Tt)u02
H1
0for t[t1,˜
T]
Then Q(t)≥P(t)>0for t[t1,˜
T],Q(t)=P(t)−P(0) >0and Q′′(t)=P′′(t)>0.
Hence from (24) we observe,
Q(t)Q′′(t)q
2(Q(t))2≥P(t)2q(dJ(u0)) + P′′(t)( ˜
Tt)u02
H1
0>0(25)
Now define
R(t)=Q(t)q2
2
Then,
R(t)=q2
2Q(t)q
2Q(t)
and
R′′(t)=q2
2Q(t)q+2
2q
2(Q(t))2−Q(t)Q′′(t)<0
Hence
R
(
t
)is a concave function in [
t1,˜
T
]for any sufficiently large
˜
T >t
1
. Also since
R
(
t1
)
>
0
and
R′′
(
t1
)
<
0, there appears a finite time
T>t
1>
0having
limtT
R
(
t
)=0. That yields
limtT
Q(t)=+, which in turn gives limtT
P(t)=+. Hence we get
lim
tT
u2
H1
0=+.
To obtain an upper limit for blow-up time we define,
S(t)=P(t)+(Tt)u02
H1
0+σ(t+φ)2for t[0,T
]
where the constants σ, φ > 0will be given later.
Then,
S(t)=u2
H1
0−∥u02
H1
0+2σ(t+φ)>2σ(t+φ)>0(26)
also by (23) we get,
S′′(t)2q(dJ(u0))+2qt
0ut2
H1
0dt +2σ(27)
By Schwartz’s inequality, we have,
t
0
d
dtu2
H1
0dt 2t
0u2
H1
0dt t
0ut2
H1
0dt (28)
https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
119
Therefore,
(S(t))2=4
1
2t
0
d
dtu2
H1
0dt +σ(t+φ)2
4t
0
d
dtu2
H1
0dt +σ(t+φ)2t
0
d
dtut2
H1
0dt +σ
=4
S(t)(Tt)u02
H1
0t
0
d
dtut2
H1
0dt +σ
4S(t)t
0
d
dtut2
H1
0dt +σ(29)
Now by applying (27) and (29) we can see that,
S(t)S′′(t)q
2(S(t))2≥S(t)(2q(dJ(u0)) 2σ(q1))
If σ0,q(dJ(u0))
q1, then
S(t)S′′(t)q
2(S(t))2>0.
Also we have
S
(0) =
Tu02
H1
0
+
σφ2>
0and
S
(0) = 2
σφ >
0. Then by Levine’s Concavity approach,
we obtain the upper bound for blow-up as,
TS(0)
(q
21)S(0) =
Tu02
H1
0
(q2)σφ +φ
q2
Therefore,
Tσφ2
(q2)σφ −∥u02
H1
0
thus we must have
φ(q1)u02
H1
0
q(q2)(dJ(u0)),
Let υ=σφ 0,q(dJ(u0))φ
q1, then Tφυ
(q2)υ−∥u0H1
0
.
Now let h(φ, υ)= φυ
(q2)υ−∥u0H1
0
. Since his monotonically decreasing concerning υ, we have
inf
{(φ,υ)}h(φ, υ) = inf
{φ}hφ, q(dJ(u0))φ
q1
= inf
{b}k(φ)
where,
k(φ)=hφ, q(dJ(u0))φ
q1=φ2q(dJ(u0))
q(q2)(dJ(u0))φ(q1)u0H1
0
now since k(φ)takes the minimum at φ=2(q1)u0H1
0
q(q2)(dJ(u0)) we can conclude that,
Tk(φ)=
4(q1)u02
H1
0
q(q2)2(dJ(u0)).
The following theorem show that the weak solution of the system blow-up when the initial energy of
the system is critical.
Theorem 5. (Blow up for J(u0)=d)
Let
u0W2,p
0
(Ω)
\{
0
},J
(
u0
)=
d
and
I
(
u0
)
<
0, then the weak solution
u
(
t
)of problem (1) blows up in
the sense, there appears a T<such that limtT
u2
H1
0=.
https://doi.org/10.17993/3ctic.2022.112.108-122
Proof.Since
J
(
u0
)=
d>
0and
J
(
u
)is continuous with respect to
t
, there appears a
t0
with
J
(
u
(
x, t
))
>
0for 0
<tt0
. Also, it is easy to see
I
(
u
(
t
))
<
0for every
t
. Therefore from the energy
inequality, t0
0uτ2
H1
0dτ +J(u(t0)) <J(u0)=d, it follows that J(u(t0)) <d.
Now choose t=t0as initial time, we have J(u(t0)) <dand I(u(t0)) <0. Now define
P(t)=t
t0u2
H1
0for t>t
0
and the rest of proof resembles the proof of Theorem (4).
ACKNOWLEDGMENT
The first author acknowledges the Council of Scientific and Industrial Research(CSIR), Govt. of India,
for supporting by Junior Research Fellowship(JRF).
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[4]
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Fugeng Zeng, Qigang Deng, an Dongxiu Wang,(2022). Global Existence and Blow
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Up for
the Pseudo
-
parabolic p(x)
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Laplacian Equation with Logarithmic Nonlinearity, Journal of Nonlinear
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Gopala Rao, V.R., and Ting, T. W.,(1972). Solutions of pseudo-heat equations in the whole
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p-biharmonic parabolic equation, Appl. Math. Lett., 64, 198-204.
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Jiaojiao Wang, and Changchun Liu,(2019). p-Biharmonic parabolic equations with logarithmic
nonlinearity, Electronic J. of Differential Equations, 08, 1-18.
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Lakshmipriya Narayanan, and Gnanavel Soundararajan,(2022). Nonexistence of global
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viscoelastic p(x)-Laplacian equation with logarithmic, nonlinearity Discontinuity, Nonlinearity, and
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Lakshmipriya, N., Gnanavel, S., Balachandran, K., and Yong-Ki Ma,(2022) Existence
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https://doi.org/10.17993/3ctic.2022.112.108-122
3C TIC. Cuadernos de desarrollo aplicados a las TIC. ISSN: 2254-6529
Ed. 41 Vol. 11 N.º 2 August - December 2022
120
Therefore,
(S(t))2=4
1
2t
0
d
dtu2
H1
0dt +σ(t+φ)2
4t
0
d
dtu2
H1
0dt +σ(t+φ)2t
0
d
dtut2
H1
0dt +σ
=4
S(t)(Tt)u02
H1
0t
0
d
dtut2
H1
0dt +σ
4S(t)t
0
d
dtut2
H1
0dt +σ(29)
Now by applying (27) and (29) we can see that,
S(t)S′′(t)q
2(S(t))2≥S(t)(2q(dJ(u0)) 2σ(q1))
If σ0,q(dJ(u0))
q1, then
S(t)S′′(t)q
2(S(t))2>0.
Also we have
S
(0) =
Tu02
H1
0
+
σφ2>
0and
S
(0) = 2
σφ >
0. Then by Levine’s Concavity approach,
we obtain the upper bound for blow-up as,
TS(0)
(q
21)S(0) =
Tu02
H1
0
(q2)σφ +φ
q2
Therefore,
Tσφ2
(q2)σφ −∥u02
H1
0
thus we must have
φ(q1)u02
H1
0
q(q2)(dJ(u0)),
Let υ=σφ 0,q(dJ(u0))φ
q1, then Tφυ
(q2)υ−∥u0H1
0
.
Now let h(φ, υ)= φυ
(q2)υ−∥u0H1
0
. Since his monotonically decreasing concerning υ, we have
inf
{(φ,υ)}h(φ, υ) = inf
{φ}hφ, q(dJ(u0))φ
q1
= inf
{b}k(φ)
where,
k(φ)=hφ, q(dJ(u0))φ
q1=φ2q(dJ(u0))
q(q2)(dJ(u0))φ(q1)u0H1
0
now since k(φ)takes the minimum at φ=2(q1)u0H1
0
q(q2)(dJ(u0)) we can conclude that,
Tk(φ)=
4(q1)u02
H1
0
q(q2)2(dJ(u0)).
The following theorem show that the weak solution of the system blow-up when the initial energy of
the system is critical.
Theorem 5. (Blow up for J(u0)=d)
Let
u0W2,p
0
(Ω)
\{
0
},J
(
u0
)=
d
and
I
(
u0
)
<
0, then the weak solution
u
(
t
)of problem (1) blows up in
the sense, there appears a T<such that limtT
u2
H1
0=.
https://doi.org/10.17993/3ctic.2022.112.108-122
Proof.Since
J
(
u0
)=
d>
0and
J
(
u
)is continuous with respect to
t
, there appears a
t0
with
J
(
u
(
x, t
))
>
0for 0
<tt0
. Also, it is easy to see
I
(
u
(
t
))
<
0for every
t
. Therefore from the energy
inequality, t0
0uτ2
H1
0 +J(u(t0)) <J(u0)=d, it follows that J(u(t0)) <d.
Now choose t=t0as initial time, we have J(u(t0)) <dand I(u(t0)) <0. Now define
P(t)=t
t0u2
H1
0for t>t
0
and the rest of proof resembles the proof of Theorem (4).
ACKNOWLEDGMENT
The first author acknowledges the Council of Scientific and Industrial Research(CSIR), Govt. of India,
for supporting by Junior Research Fellowship(JRF).
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