1 INTRODUCTION
Additive number theory is a relatively young discipline and has seen some spectacular progress in the
last few decades. The aim of this short article is to give a brief description of some of the major results
and also list a few problems that are easy to state and undertstand but not clear how they can (or will)
be solved. The goal is to stimulate and kindle interest in the subject. This is a review paper and most
of the material is well known. The papers of Melvyn B. Nathanson [3], [4], Kannan Soundararajan [5],
Andrew Granville [2], and H V Chu et al [1] are especially informative and detailed. We begin with a
well known and popular result, the Friendship theorem. Friendship Theorem
At any party with at least six people, there are three people who are all either mutual acquaintances
(each one knows the other two) or mutual strangers.
Ramsey Theory
For any given integer
c
, any given integers
n1,...,n
c
, there is a number,
R
(
n1,...,n
c
), such that if the
edges of a complete graph of order
R
(
n1,...,n
c
)are coloured with
c
different colours, then for some
i
between 1and c, it must contain a complete subgraph of order niwhose edges are all colour i.
The special case above has c=2and n1=n2=3.
Broad Philosophy
Can find order in disorder. Are there such analogs in Number theory? Answer is
YES. Order is Arithmetic progressions (APs). 3-AP means 3 consecutive terms in AP and k-AP means
k consecutive terms in AP. One can ask under what conditions will a set A of integers contain atleast
one 3-AP? No 3-AP at all? Infinitely many 3-APs?
Broadly, given a sufficiently large set of integers
A
we interested in understanding additive patterns
that appear in
A
. An important example is whether
A
contains non-trivial arithmetic progressions of
some given length k.
Reason
: They are quite indestructible structures. They are preserved under translations and dilations
of A, and they cannot be excluded for trivial congruence reasons.
For example the pattern
a
,
b
and
a
+
b
all being in the set seems quite close to the arithmetic progression
case
a, b,
(
a
+
b
)
/
2, but the former case can never occur in any subset of the odd integers (and such
subsets can be very large).
Other questions
: Whether all numbers can be written as a sum of
s
elements from a given set
A
. For
example, all numbers are sums of four squares, nine cubes etc. Waring’s problem and the Goldbach
conjectures are two classical examples. In the same spirit, given a set
A
of
N
integers we may ask for
information about the sumset
A
+
A
:=
{a
+
b
:
a, b ∈A}
. If there are not too many coincidences, then
we may expect
|A
+
A|N2
. But when
A
is an AP,
|A
+
A|≤
2
|A|−
1. The subject may be said to
begin with a beautiful result of van der Waerden (1927).
Theorem 1. (van der Waerden)
. Let
k
and
r
be given. There exists a number
N
=
N
(
k, r
)such
that if the integers in [1
,N
]are colored using
r
colors, then there is a non-trivial monochromatic k term
arithmetic progression.
van der Waerden’s proof was by an ingenious elementary induction argument on
k
and
r
. The proof
does not give any good bound on how large
N
(
k, r
)needs to be. A more general result was subsequently
found by Hales and Jewett (1963), with a nice refinement of Shelah (1988), but again the bounds for
the van der Waerden numbers are quite poor.
Theorem 2. (Schur)
. Given any positive integer
r>
1, if
N≥N
(
r
)and the integers in [1
,N
]are
colored using rcolors then there is a monochromatic solution to x+y=z.
Lemma 1.
Suppose that the edges of the complete graph
KN
are colored using
r
colors. If
N≥N
(
r
)
then there is a monochromatic triangle.
Proof:
We will use induction on
r
. It is very well known that if
r
=2and
N≥
6then there is a
monochromatic triangle. Suppose we know the result for
r−
1colorings, and we need
N≥N
(
r−
1)
for that result. Pick a vertex. There are
N−
1edges coming out of it. So for some color there are
[(
N−
1)
/r
]+1edges starting from this vertex having the same color. Now the complete graph on the
https://doi.org/10.17993/3cemp.2022.110250.186-196
other vertices of these edges must be colored using only
r−
1colors. Thus if
N≥rN
(
r−
1)
−r
+2we
are done.
Proof of Schur’s Theorem:
Consider the complete graph on
N
vertices labeled 1through
N
.
Color the edge joining
a
to
b
using the color of
|a−b|
. By our lemma, if
N
is large then there is a
monochromatic triangle. Suppose its vertices are
a<b<c
, then (
c−a
)=(
c−b
)+(
b−a
)is a solution,
proving Schur’s theorem.
Theorem 3. (Hales-Jewett)
. Let
k
and
r
be given. There exists a number
N
=
N
(
k, r
)such that if
the points in [1
,k
]
N
are colored using
r
colors then there is a monochromatic “combinatorial line”. Here
a combinatorial line is a collection of
k
points of the following type: certain of the coordinates are fixed,
and a certain non-empty set of coordinates are designated as “wildcards” taking all the values from 1 to
k.
A picturesque way of describing the Hales-Jewett theorem is that a “tic-tac-toe” game of getting k in
a row, played by r players, always has a result in sufficiently high dimensions. Since there is obviously
no disadvantage to going first, the first player wins; but no constructive strategy solving the game
is known. One can recover van der Waerden’s theorem by thinking of [1
,k
]
N
as giving the base
k
digits(shifted by 1) of numbers in [0,k
N−1].
Erdos and Turan proposed a stronger form of the van der Waerden, partly in the hope that the
solution to the stronger problem would lead to a better version of van der Waerden’s theorem.
The Erdos-Turan conjecture
: Let
δ
and
k
be given. There is a number
N
=
N
(
k, δ
)such that any
set A⊂[1,N]with |A|≥δN contains a non-trivial arithmetic progression of lenghth k.
In 1953, Roth proved the Erdos - Turan conjecture in the case k=3.
Theorem 4. (Roth)
. There exists a positive constant
C
such that if
A⊂
[1
,N
]with
|A|≥CN/ log log N
then
A
has a non-trivial three term AP. In other words,
N
(
δ,
3)
≤exp
(
exp
(
C/δ
)) for some positive
constant C.
This stronger result does in fact give a good bound on the van der Waerden numbers for
k
=3. We
know now(Bourgain), that
|A|N
(
log log N/log N
)
1/2
suffices. Thus the double exponential bound
can be replaced by a single exponential.
Let
r3
(
N
)denote the size of the largest subset of [1
,N
]having no non-trivial three term APs. Then
as mentioned above,
r3
(
N
)
Nlog log N/log N
. What is the true nature of
r3
(
N
)?Ifwepicka
random set
A
in [1
,N
]we may expect that it has about
|A|3/N
three term APs. This suggests that
r3
(
N
)is perhaps of size
N1
3
. However, in 1946 Behrend found an ingenious construction that does
much much better.
Theorem 5. (Behrend)
. There exists a set
A⊂
[1
,N
]with
|A|Bexp
(
−c√logN
)containing no
non-trivial three term arithmetic progressions. In other words r3(N)Nexp(−c√log N).
Roth’s proof is based on Fourier analysis. It falls naturally into two parts: either the set
A
looks
random in which case we may easily count the number of three term progressions, or the set has some
structure which can be exploited to find a subset with increased density. The crucial point is that the
idea of randomness here can be made precise in terms of the size of the Fourier coefficients of the set.
This argument is quite hard to generalize to four term progressions (or longer), and was only extended
recently with the spectacular work of Gowers.
Returning to the Erdős-Turan conjecture, the next big breakthrough was made by Szemeredi who
in 1969 established the case
k
=4, and in 1975 dealt with the general case
k≥
5. His proof was a
tour-de-force of extremely ingenious and difficult combinatorics. One of his ingredients was van der
Waerden’s theorem, and so this did not lead to a good bound there.
Theorem 6. (Szemeredi)
. Given
k
and
δ>
0, there exists
N
=
N
(
k, δ
)such that any set
A⊂
[1
,N
]
with |A|≥δN contains a non-trivial kterm arithmetic progression.
https://doi.org/10.17993/3cemp.2022.110250.186-196
3C Empresa. Investigación y pensamiento crítico. ISSN: 2254-3376
Ed. 50 Vol. 11 N.º 2 August - December 2022
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